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55 lines
1.3 KiB
Markdown
55 lines
1.3 KiB
Markdown
# 6.3 pwn xdctf2015 pwn200
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- [题目复现](#题目复现)
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- [ret2dl-resolve 原理及题目解析](#ret2dlresolve-原理及题目解析)
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- [Exploit](#exploit)
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- [参考资料](#参考资料)
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## 题目复现
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出题人在博客里贴出了源码，如下：
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```C
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#include <unistd.h>
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#include <stdio.h>
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#include <string.h>
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void vuln()
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{
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char buf[100];
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setbuf(stdin, buf);
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read(0, buf, 256);
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}
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int main()
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{
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char buf[100] = "Welcome to XDCTF2015~!\n";
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setbuf(stdout, buf);
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write(1, buf, strlen(buf));
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vuln();
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return 0;
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}
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```
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使用下面的语句编译：
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```
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$ gcc -m32 -fno-stack-protector pwn200.c
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```
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checksec 如下：
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```
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$ checksec -f a.out
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RELRO STACK CANARY NX PIE RPATH RUNPATH FORTIFY Fortified Fortifiable FILE
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Partial RELRO No canary found NX enabled PIE enabled No RPATH No RUNPATH No 0 2 a.out
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```
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在开启 ASLR 的情况下把程序运行起来：
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```
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$ socat tcp4-listen:10001,reuseaddr,fork exec:./a.out &
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```
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这题提供了二进制文件而没有提供 libc.so，而且也默认找不到，所以只能依靠 DynELF 来做。
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## ret2dl-resolve 原理及题目解析
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## Exploit
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## 参考资料
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- [Return-to-dl-resolve](http://pwn4.fun/2016/11/09/Return-to-dl-resolve/)
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